Question

prove that 4ab=(a+b)²-(a-b)²

Answer 1

LHS = 4ab

RHS = (a+b)^2 -(a-b)^2
= (a^2 +b^2+2ab) -( a^2+b^2-2ab)
= a^2+b^2 +2ab -a^2 -b^2 +2ab
=4ab
then , LHS = RHS
4ab. = 4ab

Answer 2

Solution :

RHS = ( a + b )² - 4ab

= a² + b² + 2ab - 4ab

= a² + b² - 2ab

= ( a - b )²

= RHS

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