Math, asked by ombinayakjena, 8 months ago

prove that 4cos 12°.cos48°.cos72°=cos36°

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Answered by harpal2786

Answer:

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Step-by-step explanation:

4cos 12^ocos 48^ocos 72^o = 2(2cos 12^ocos 48^o)cos 72^o = 2[cos (12 + 48) + cos(12 - 48)]cos 72^o = 2[cos 60^o + cos 36^o]cos 72^o = 2cos 60^ocos 72^o ..

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prove that 4cos 12°.cos48°.cos72°=cos36°​

Answers

prove that 4cos 12°.cos48°.cos72°=cos36°