Question

prove that 4cot45°-sec square 60°-sin30°=-1/4

Answer 1

4cot 45° - sec^2 60° - sin^2 30° = -1 / 4

4× 1 - (2)^2 - (1/2)^2

4 - 4 - 1/4

-1/4. = RHS

Thanks