Question

prove that 4n and never ends with the digit 0​

Answer 1

Step-by-step explanation:

  4n = 2 × 2n

the only prime factorization of 4n is 2×2n .

 5 does not occur in the prime factorization of 4n for any value of n.

but we know that any positive integer ending with zero is divisible by 5 and 2.

          here is 2 but not 5.

∴ we can conclude that , 4n does not end with the digit zero for any natural number n.

            HOPE THIS HELPS!!!