Question

Prove that 4sin 30 sin. 60 + 3 cos 60 tan 45º = 2sec 60 -cos ec 90​

Answer 1

Answer:

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Answer 2

Answer:

if above question is as below:

4sin30×sin60 + cos60 × tan45 = 2sec60 - cosec90

solution:- tan 45= 1 ,cosec90=1 ,sin60=root3/2 , sin30=1/2 , cos60=1/2 , sec60=2

Now,

LHS:- 4×1/2×root3/2 + 3×1/2× 1

root3 + 3/2

( 2root3 + 3)/2=3

RHS:- 2×2 - 1

4-1=3