prove that 4sin30° sin^2 60° + 3cos60° tan 45°= 2sec^2 45°-cosec90°
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4(1/2) × (root 3/2)^2 + 3(1/2) × 1 = 2(root 2)^2 - 1
2 × 3/4 + 3/2 = 2×2 - 1
3/2 + 3/2 = 4 - 1
6/2 = 3
3 = 3
Hence proved...
Thanks
2 × 3/4 + 3/2 = 2×2 - 1
3/2 + 3/2 = 4 - 1
6/2 = 3
3 = 3
Hence proved...
Thanks
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3
This is the answer.............hope u give me a thanks
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