Prove that 4x-3y-1 = 0, 6x+8y +1 = 0 and
2x +11y+2 = 0 meet at a point.
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Step-by-step explanation:
Let' solve this system of equations
4x - 3y - 1 = 0 ........ (1)
2x + 11y + 2 = 0 .... (2)
2 × (2) - (1) :
22y + 3y + 4 + 1 = 0 ⇒ y = - 0.2
2x + 11(- 0.2) + 2 = 0 ⇒ x = 0.1
( 0.1 , - 0.2 ) -----> 6x + 8y + 1 = 0
6(0.1) + 8( - 0.2 ) + 1 = 0
0.6 - 1.6 + 1 = 0
0 = 0
Three lines meet at ( 0.1 , - 0.2 )
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