Math, asked by polisettyshowrilu198, 4 months ago

prove that √5+√11 is rational​

Answers

Answered by Anonymous
0

Let us consider √5 + √11 is not irrational

then it becomes √5 + √11 is a rational

we know that

p/q where p , q belongs to integers and q ≠ 0

Squaring on both sides

(√5 + √11 ) 2 = ( p/q ) 2

Use ( a + b ) 2 formula

(√5)2 + (√11)2 + 2 × √5 × √11 = p2 / q2

5 + 11 + 2 × √55 = p2 / q2

16 + 2 × √55 = p2 / q2

2 × √55 = p2 / q2 - 16 / 1

√55 = p2 - 16 q2 / q2

LHS = √11 where it is irrational because " 11 " is

not a perfect square .

RHS = p2 - 16 q2 / q2

It becomes rational because it is in the form of p/q

Our contradiction is wrong

Our Assumption is wrong

√5 + √11 is an irrational

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Answered by suhanimoond99
0

Answer:

well it's not ..u can also do it by as root 5 + root 11=5.5526....hence it can be written in p/q form where p nd q are integers and q is not equal to zero ...so hence it's rational

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