Question

Prove that 5-2√3 irrational​

Answer 1

taken √3 irrational

rational-irrational=irrational hence it's irrational

OR

let us contradict it to be a rational no.,so,it can be represented as

$5 - 2 \sqrt{3} = \frac{a}{b}$

$5 - \frac{a}{b} = 2 \sqrt{3}$

lhs is rational whereas rhs is irrational

so, our contradiction was wrong and hence

it's an irrational number

Answer 2

Answer:

hope this is helpful!

Hence, proved.