Prove that 5 - 2√3 is an irrational number.
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718
Nice question
let,
5 - 2√3 be a rational number.
.°. 5 - 2√3 = p/q [ where p and q are integer , q ≠ 0 and q and p are co- prime number ]
=> - 2√3 = p/q -5
=>- 2√3 = p - 5q / q
=> √3 = p - 5q / - 2q
we know that p/q is a rational number.
.°. √3 is also a rational number.
This contradicts our assumption
5 - 2√3 is an irrational number
thank you !! sweet dreams
===================================
let,
5 - 2√3 be a rational number.
.°. 5 - 2√3 = p/q [ where p and q are integer , q ≠ 0 and q and p are co- prime number ]
=> - 2√3 = p/q -5
=>- 2√3 = p - 5q / q
=> √3 = p - 5q / - 2q
we know that p/q is a rational number.
.°. √3 is also a rational number.
This contradicts our assumption
5 - 2√3 is an irrational number
thank you !! sweet dreams
===================================
Answered by
269
hope it will be helpful
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