Prove that 5-2√3is an irrational number
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2√3 is a irrational number
and 5 is a rational number
so Rational -Irrationnal = Irrationnal
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Solution:
Let us assume given number
(5-2√3 ) is rational.
5-2√3 = a/b
where a,b are integers, and
b≠0
=> -2√3 = a/b - 5
=> -2√3 = (a-5b)/b
=> √3 = (a-5b)/(-2b)
=> √3 = (5b-a)/2b
Since , a,b are integers ,
(5b-a)/2b is a rational number,so, √3 is rational.
But , It contradicts the fact that
√3 is an irrational.
Therefore,
5-2√3 is an irrational.
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