prove that 5+✓2 is a irrational no
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Answered by
2
hey mate here is your answer
so here;
we have to prove 5+√2 is irrational no.
let us take the opposite
5+√2 is rational no.
hence 5+√2 can be written in the form a/b
where a and b are co-prime
hence;
5+√2=a/b
√2=a/b-5
√2=a-5b/b
therefore,LHS is irrational & RHS is rational no.
LHS is not equal to RHS
thia contradicts that 5+√2 is irrational no
hence 5+√2 is irrational
HENCE THE PROOF
hope this helps u mate if it does pls mark as brainliest
be blessed
good night dear mate❤❤
so here;
we have to prove 5+√2 is irrational no.
let us take the opposite
5+√2 is rational no.
hence 5+√2 can be written in the form a/b
where a and b are co-prime
hence;
5+√2=a/b
√2=a/b-5
√2=a-5b/b
therefore,LHS is irrational & RHS is rational no.
LHS is not equal to RHS
thia contradicts that 5+√2 is irrational no
hence 5+√2 is irrational
HENCE THE PROOF
hope this helps u mate if it does pls mark as brainliest
be blessed
good night dear mate❤❤
Answered by
3
Answer:
Step-by-step explanation:
Let √2+√5 be a rational number.
A rational number can be written in the form of p/q where p,q are integers.
√2+√5 = p/q
Squaring on both sides,
(√2+√5)² = (p/q)²
√2²+√5²+2(√5)(√2) = p²/q²
2+5+2√10 = p²/q²
7+2√10 = p²/q²
2√10 = p²/q² - 7
√10 = (p²-7q²)/2q
p,q are integers then (p²-7q²)/2q is a rational number.
Then √10 is also a rational number.
But this contradicts the fact that √10 is an irrational number.
.°. Our supposition is false.
√2+√5 is an irrational number.
Hence proved.
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