prove that, 5-2root 3 is irrational
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Solution:
Let us assume 5-2√3 is
rational.
5-2√3 = a/b [ where a,b are integers and b ≠ 0 ]
=> 2√3 = 5-a/b
=> 2√3 = (5b-a)/b
=> √3 = (5b-a)/2b
Since , a,b are integers ,
(5b-a)/2b is rational ,so √3 is
rational.
But , this contradicts that the
√3 is irrational.
Therefore.
5-2√3 is rational.
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