Question

Prove that 5-3√2 is an irrational no.
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Answer 1

beacause under root 2 cant be solved so it is irrrstional

Answer 2

Answer:

Let 5-3√2 is rational

so 5-3√2 = p/q. (where p and q are integers)

√2 = p/5q x 3

this contradiction that p/5q x 3 is a rational number so √2 also

but this contradicts fail that √2 is irrational

5-3√2 is irrational