Prove that (5+3√2) is irrational.
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Let 5 + 3√2 be a rational number
5 + 3√2 = P / q
Where q ≠ 0 and p and q are co- prime number
3√2 = P / q - 5√2 = p -5q / 3q
p and q are integers and g ≠ 0p -5q / 3q is rational number √2 is a rational number but √2 is irrational number.This contradiction has arisen because our assumption is wrong. So we conclude that 5+3√2 is an irrational number.
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