Question

prove that 5 - 3√2 is irrational​

Answer 1

Answer:

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Answer 2

$5 - 3 \sqrt{2} = \frac{a}{b} \\ - 3 \sqrt{2} = \frac{a - 5b}{b} \\ \sqrt{2} = \frac{a - 5b}{ - 3b}$

Here rhs is rational so lhs must also be rational

But this contradicts the fact that √2 is irrational

this contradiction has occurred because of our wrong assumption

hence, 5-3√2 is irrational...

hope it helps...