Prove that 5-3√3\7
is irrational
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Answer:
Step-by-step explanation:
assume the no. to be a rational no.
now equate it to a/b (where a and b are integers and b is not equal to 0)
bring root 3 to one end and rest of the statement to other.
then conclude:
this contradicts the fact that root 3 is an irrational no.
hence the expression is also irrational
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