Question

Prove that 5 - 3√5 is an irrational number​

Answer 1

suppose 5-3root5 is rational number = r.

=》r = 5-3root5

r-5/3 = root5

As we know root 5 is irrational no. and

r-5/3 is rational no. (bcz r-5 & 3 belongs to integers and q is not = 0)

a irrational no. cant be equal to a rational no. so our supposition is wrng

=》5-3root5 is irrational no.

MARK ME AS BRAINLIST

Answer 2

Answer:

let 5-3√5 be a regional number

so 5-3√5 =p/q (q=0)

-3√5 =p/q -5

√5=p/3q-5/3

where p and q are lntegers

so p/3q-5/3 a rational number

so √5 also rational number

but our belief is wrong

because√5 is an irrational number