Question

prove that 5-3/7√3 is an irrational no.<br />Plzz give me fast answer I will choose as brainlist the person who gives right answer

Answer 1

let it be a rational number
$5 - \frac{3}{7} \sqrt{3} = \frac{a}{b}$
$= > - \frac{3}{7} \sqrt{3 } = \frac{a}{b} - 5$
$= > \frac{3}{7} \sqrt{3} = \frac{5b - a}{b}$
$\sqrt{3} = \frac{7(5b - a)}{3b}$
it seems that √3 is rational
so our assumption get wrong because √3 is irrational number so 5-3/7√3 is irrational

Answer 2

Answer:

here is ur answer