Question

Prove that 5 –3/7 √3
is an irrational number.​

Answer 1

Step-by-step explanation:

5- 3/7√3

{35√3 - 3√7 }/ 7√3

Answer 2

Answer:

let it rational

P/Q is also rational

5-3/7√3=P/Q

7×5-3√3=7P/Q

35-3√3=7P/Q

-3√3=7P/Q-35

-3√3=7P-35Q/Q

-√3=7P-35Q/3Q

7P-35Q/3Q is rational number but -√3 is irrational This contradiction has arrived because our assumption is wrong Hence 5-3/7√3 is irrational