Question

prove that 5+ 3√7 is an irrational number where √7 is irrational​

Answer 1

Answer:

3√5-7=p/q {where, p and q are integers having no common factors}. where , √5 and p+7q/3q are rational numbers. ... Therefore,3√5-7 is an irrational no.

Step-by-step explanation:

Let given no is rational

so 3+√7/5=p/q

√7=5p/q-3

√7=5p-3q/q

hence 5p-3q/qis rational it's mean that √7is also rational, but we know that √7 is irrational this contradict our assumption that 3+√7/5 is rational , hence it is irrational