Question

prove that 5√3 is a irrational number​

Answer 1

Step-by-step explanation:

Let 5√3 = a/b, be a rational number where a and b are integers and co primes , b not equal to 0

5√3 = a/b

√3 = a/(b*5)

a,b and 5 are integers so a/(b*5) is a rational number.

Therefore, √3 is a rational number but √3 is irrational number.

This Contradiction occurs due to our wrong assumption.

Hence, 5√3 is irrational number.

Hence, proved.