prove that 5-√3 is an irrational number
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Answered by
13
Hey friend!! :)))
Suppose 5-√3 is rational
5-√3=p/q, where p and q are co-primes
therefore..
-√3=p/q+5
LHS=Irrational and RHS =Rational
Hence proved...
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Answered by
4
Answer:
Let 5 - √3 be rational,
Then, 5 - √3 can be expressed as where, p and q are co-prime integers and
q ≠ 0,
we have,
(picture)
As p and q are integers, 5q - p is also an integer
is a rational number.
But √3 is an irrational number, so the equality is not possible.
This contradicts our assumption, that 5 - √3 is a rational number.
Therefore, 5 - √3 is an irrational number.
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