prove that √ 5+3 is an irrational number
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Let us prove that 3
is irrational. The question will automatically follow.
We prove it by contradiction.
Assume 3
is a rational number.
Thus, 3=q/p
where p,q are co-prime integers.
Thus ⟹3q
2
=p
2
This means p
2
is a multiple of 3.
As p is an integer, p also must have a factor 3.
We can say p=3λ, where λ is a constant
Thus (3λ)
2
=3q
2
,
3λ
2
=q
2
Again, we see q
2
∣ 3 which means q ∣ 3.
What do we see?
Both p and q have a common factor 3!
This is not in agreement to our initial assumption that p and q must be co-prime.
So,
3
must be irrational.
Multiplying a rational number(in this case 5) with an irrational, makes the whole number irrational.
So 5
3
is irrational.
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