prove that 5 + √3 is irrational.
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Answered by
1
Let 5+√3 be rational number.
A rational number can be written in the form of p/q where p,q are integers.
5+√3=p/q
√3=p/q-5
√3=(p-5q)/q
p,q are integers,then (p-5q)/q is a rational number.
Then,√3 is also a rational number.
But this contradicts the fact that √3 is an irrational number.
Therefore,our supposition is false.
So,5+√3 is an irrational number.
Hence proved.
A rational number can be written in the form of p/q where p,q are integers.
5+√3=p/q
√3=p/q-5
√3=(p-5q)/q
p,q are integers,then (p-5q)/q is a rational number.
Then,√3 is also a rational number.
But this contradicts the fact that √3 is an irrational number.
Therefore,our supposition is false.
So,5+√3 is an irrational number.
Hence proved.
Answered by
0
Rule of an irrational no. is that it should be terminating or non terminating and non recurring
root 3 satisfy this condition
any no. added with an irrational will be an ireational so the ans is irrational
root 3 satisfy this condition
any no. added with an irrational will be an ireational so the ans is irrational
Anonymous:
Hope it helps
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