Prove that √5+√3 is irrational
Answers
Answered by
0
Thus so
_____________________________________________________________
. THE ANS IS IT S
. ( REFER ATTACHMENT )
. Hope it helps
. Mark as brainliest if helpful .
_____________________________________________________________
. THE ANS IS IT S
. ( REFER ATTACHMENT )
. Hope it helps
. Mark as brainliest if helpful .
Attachments:
Answered by
2
♧♧HERE IS YOUR ANSWER♧♧
We will prove it by contradiction.
Let us consider :
√5 + √3 = p/q, where p and q are integers such that q ≠ 0.
Now,
√5 + √3 = p/q
=> √5 = p/q - √3
Squaring, we get :
(√5)² = (p/q - √3)²
=> 5 = (p²/q²) - 2√3(p/q) + 3
=> 2√3(p/q) = (p²/q²) - 2
=> √3 = p/(2q) - (2q)/p,
which implies that √3 is a rational number.
Thus, √5 + √3 is an irrational number.
Hence, proved.
♧♧HOPE THIS HELPS YOU♧♧
We will prove it by contradiction.
Let us consider :
√5 + √3 = p/q, where p and q are integers such that q ≠ 0.
Now,
√5 + √3 = p/q
=> √5 = p/q - √3
Squaring, we get :
(√5)² = (p/q - √3)²
=> 5 = (p²/q²) - 2√3(p/q) + 3
=> 2√3(p/q) = (p²/q²) - 2
=> √3 = p/(2q) - (2q)/p,
which implies that √3 is a rational number.
Thus, √5 + √3 is an irrational number.
Hence, proved.
♧♧HOPE THIS HELPS YOU♧♧
Steph0303:
suer bhai
Similar questions