Math, asked by adi43194, 1 month ago

Prove that 5 + √3 is irrational.​

Answers

Answered by mathgenius11
0

Step-by-step explanation:

5 +  \sqrt{3 }  \\ 5 +  \sqrt{3}  \times  \frac{5 +  \sqrt{3} }{5 -  \sqrt{3} }  \\  \frac{25 + 3 + 10 \sqrt{3} }{5 -  \sqrt{3} }  \\  \frac{28 + 10 \sqrt{3} }{5 -  \sqrt{3} }

so ,multiply by conjugate but squreroot is remaining so this number irrational

Answered by kumariipsita
3

Answer:

Let us assume the given number be rational and we will write the given number in p/q form

⇒5- √3= p/q

⇒√3= 5q- p

q

We observe that LHS is irrational and RHS is rational, which is not possible.

This is contradiction.

Hence our assumption that given number is rational is false

⇒5− √3 is irrational

Step-by-step explanation:

Hope it will help you..

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