Prove that 5+√3 is irrational
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Answer:
let us assume to the contrary that 5-root3 is rational
=>5-root3=a/b (where a and b are co primes and b not equal to zero)
=>root3=5b-a/b
Here a and b are integers, so 5-a/b is rational , hence root3 is also rational.
But this contradicts our fact that root 3 is irrational.
This contradiction has arisen bcoz of our incorrect assumption that 5-root3 is rational.
hence 5-root3 is irrational
Answered by
1
Step-by-step explanation:
Let us assume the given number be rational and we will write the given number in p/q form
⇒5− √3=p/q
=√3=5q-p/q
We observe that LHS is irrational and RHS is rational, which is not possible.
This is contradiction.
Hence our assumption that given number is rational is false
⇒5− √3 is irrational
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