prove that 5/√7 is irrational
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Let us assume that 5√7 is rational number
Hence 5√7 can be written in the form of a/b where a,b(b ≠0) are co-prime
⟹5√7=a/b
⇒√7=a/5b
But here √7 is irrational but a/5b is rational
as Rational ≠Irrational
This is a contradiction
so 5√7 is a irrational number
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