Question

Prove that : (5^a÷ 5^b)^a+b × (5^b÷5^c )^b+c × (5^c÷5^a )^a+c = 1

Answer 1

Step-by-step explanation:

LHS=RHS

PROVED

OK

MAN

..

Answer 2

Answer:

(5^a-b)^(a+b)*+(5^b-c)*(b+c)*(5^c-a)*(a+c)

=5^(a^2-b^2)*5^(b^2-c^2)*5(c^2-a^2)

=5^(a^2-b^2+b^2-c^2+c^2-a^2)

=5^0

=1