Question

prove that √5 irrational​

Answer 1

Answer:

hey mate

root 5 is a non terminating and repeating decimal and rational numbers are terminating and repeating decimal

hope it helped u

Answer 2

Answer:

"√5 is an “irrational number”.

Given:

√5

To prove:

√5 is a rational number

Solution:

Let us consider that √5 is a “rational number”.

We were told that the rational numbers will be in the “form” of \frac {p}{q}qp form Where “p, q” are integers.

So, \sqrt { 5 } = \frac {p}{q}5=qp

p = \sqrt { 5 } \times qp=5×q

we know that 'p' is a “rational number”. So 5 \times q should be normal as it is equal to p

But it did not happens with √5 because it is “not an integer”

Therefore, p ≠ √5q

This denies that √5 is an “irrational number”

So, our consideration is false and √5 is an “irrational number”."

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