Question

prove that √5 is an irrational num​

Answer 1

Here is your answer

let us consider that root 5 is a "rational number".

We were told that rational number will be in the " form" of p/q form where p and q are integers.

so,root 5 =p/q

p= root 5*q

we know that 'p' is a "rational number".so, 5 ( times q should be normal as it is equal to p).

But, it did not happens with root 5 because it is "not an integer".

therefore, p is equal to not root 5 q

this denies that root 5 is an " irrational number".

so, our consideration is false and root 5 is an " irrational number".

HOPE ,IT WILL HELP YOU