prove that ✓5 is an irrational number
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Answer:
Let √5 be rational in the form of a/b
Step-by-step explanation:
Now, √5 = a/b
Squaring on both sides,
5 = a²/b²
5b² = a² .......(1)
5 divides a²
5 divides a
Let a = 5c, for some integer c.
Putting a = 5c in eq.(1)
5b² = 25c²
5 divides b²
5 divides b [ Hence, 5 is prime
and 5 divides a²]
Thus, 5 is a common factor of a and b.
But, this contradicts the fact that a and b have no common factor other than 1.
The contradiction arises by assuming that √5 is rational.
Hence, √5 is irrational.
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