Prove that 5 is an irrational number.
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Answer:
do the same steps with root 5
Step-by-step explanation:
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√5 = r/s
suppose r and s have a common factor other than 1
now
√5 = a/b
so,
b*√5 = a
square both sides
5b² = a²
let a= 5c
5b²= 25c²
b² = 5c²
this means 5 divides b² and so 5 divides b
there's a and b have at least 5 as a common factor
this contradiction bcoz of one incorrect assumption that √5 is rational
answer hope this is helpful
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