Question

prove that √5 is an irrational number

Answer 1

I hope this helps you!
@vaibhav246

Answer 2

let root 5 is rational

root 5 =p/q

squaring

25q^2=p^2

now 25q = p


let other integer be m

p = 25m

squaring

p^2= 625m^2


25q^2 = 625m^2

q^2=25m^2

our contadiction is wrong because it has common factor 25

root 5 is irrational