Math, asked by Ash34567, 7 months ago

Prove that √5 is an irrational number

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Answered by Curious2k5
2

ANSWER:Given: √5

We need to prove that √5 is irrational

Proof:

Let us assume that √5 is a rational number.

Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0

⇒√5=p/q

On squaring both the sides we get,

⇒5=p²/q²

⇒5q²=p² —————–(i)

p²/5= q²

So 5 divides p

p is a multiple of 5

⇒p=5m

⇒p²=25m² ————-(ii)

From equations (i) and (ii), we get,

5q²=25m²

⇒q²=5m²

⇒q² is a multiple of 5

⇒q is a multiple of 5

Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√5 is an irrational number

Hence proved

P. S: SASNEHAM MALAYALI SIS....✌️EDAAVE NJN ENTE KARYA PARANJE... SIS ENN... APPO OK BRO....

Answered by ItzKpopLover
0

Step-by-step explanation:

myself ______ (◍•ᴗ•◍)

yup it has been a year maximum, hehe

because i was in 8th when i was here.

now I'm in 10th XD

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