prove that √5 is irrational
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Answer:
yes it is an irrational number
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Step-by-step explanation:
let us take √5 is rational no.
and a and b be co prime no.
√5 = a/b
so we can write b√5 = a
squaring both side {b√5 ] = a
b sq.×5 = a sq.
we know that 5 divides a also
so we can write a =2c for some integer c
then 5bsq. =5 sq.
5b sq. = 25
b sq. = 5
this mean 5 divides b also.
a and b have common factor 5
therefore √5 is irrational no.
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