Prove that√5 is irrational
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Step-by-step explanation:
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Step-by-step explanation:
to prove that √5 is irrational
let's assume that√5is rational
so we will find two co primes A and B
such that
√5=a/b
b√5=a
5b^2=a^2. (squaring on both sides)
since a^2 divides 5
so a also divides
now! let's
a=5c for some integer c
a^2=25c^2
5b^2=a^2
5b^2=25c^2
b^2=5c^2
which mean that b also divides 5
but this contradict the fact a and b are co primes
this contradiction ha arisen due to our assumption that√5 is rational
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