prove that √5 is irrational.
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√5 is a non terminating non repeating decimal so it is irrational
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Let us prove that √5 is an irrational number, by using the contradiction method. So, say that √5 is a rational number can be expressed in the form of pq, where q ≠0. So, let √5 equals pq. Where p, q are co-prime integers i.e. they do not have any common factor except '1'.
Given: Number 5.
To Prove: Root 5 is irrational.
To Prove: Root 5 is irrational.Proof: Let us assume that square root 5 is rational. Thus we can write, √5 = p/q, where p, q are the integers, and q is not equal to 0. The integers p and q are coprime numbers thus, HCF (p,q) = 1.
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