Question

Prove that √5 is irrational​

Answer 1

Prove That Root 5 is Irrational by Contradiction Method

Prove That Root 5 is Irrational by Contradiction MethodAssuming if p was a prime number and p divides a2, then p divides a, where a is any positive integer. Hence, 5 is a factor of p2. This implies that 5 is a factor of p.

Answer 2

Step-by-step explanation:

Prove that root 5 is irrational number.

•Given: √5

We need to prove that √5 is irrational

•Proof:

Let us assume that √5 is a rational number.

So it can be expressed in the form p/q where p,q are co-prime integers and q≠0

⇒ √5 = p/q

•On squaring both the sides we get,

⇒5 = p²/q²

⇒5q² = p² —————–(i)

p²/5 = q²

So 5 divides p

p is a multiple of 5

⇒ p = 5m

⇒ p² = 25m² ————-(ii)

•From equations (i) and (ii), we get,

5q² = 25m²

⇒ q² = 5m²

⇒ q² is a multiple of 5

⇒ q is a multiple of 5

Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number

√5 is an irrational number.

"Hence proved"