Prove that 5^n never ends with 0.where n is natural number
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hey mate
here is your answer
by fundamental theorem of arithmetic,the factorization of 5 is unique.which is equal to 5*1.
if the number ends with 0 then it must have 2 as factor .but you see 5 doesn't have.
hence 5ⁿ never ends with 0.
here is your answer
by fundamental theorem of arithmetic,the factorization of 5 is unique.which is equal to 5*1.
if the number ends with 0 then it must have 2 as factor .but you see 5 doesn't have.
hence 5ⁿ never ends with 0.
Anonymous:
welcome
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