prove that... ..........
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let theta = X (for typing convinince)
we know that cotX=cosX/sinX
hence cot²x-1/sin²x=(cos²x/sin²x)-1/sin²x
=>(cos²x-1)/sin²x=>-sin²x/sin²c=>-1
.
Hope this helps you.
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keep smiling.
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mark this as brainliest answer
we know that cotX=cosX/sinX
hence cot²x-1/sin²x=(cos²x/sin²x)-1/sin²x
=>(cos²x-1)/sin²x=>-sin²x/sin²c=>-1
.
Hope this helps you.
.
keep smiling.
.
mark this as brainliest answer
ganeshnasrikripdvjr9:
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Answered by
1
= cos^2a÷sin^2a- 1÷sin^2a
= cos^2a-1÷sin^2a
= -sin^2a÷sin^2a
= -1
= cos^2a-1÷sin^2a
= -sin^2a÷sin^2a
= -1
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