Prove that 5Sin²150+Cos²45+4tan²120/2Sin30.Cos60-tan135=55/6
solve with solutions
Answers
Answered by
0
Step-by-step explanation:
5Sin²150+Cos²45+4tan²120/2Sin30.Cos60-tan135
sin150 =sin(180-30)=sin30=1/2
(sin150)^2 = (1/2)^2 = 1/4
cos45=1/root2
(cos45)^2 = (1/root2)^2 = 1/2
tan120=tan(180-60)= -tan60 = -root3
(tan120)^2=(-root3)^2= 3
sin30=1/2
cos60=1/2
tan135=tan(180-45)=-tan45= -1
5Sin²150+Cos²45+4tan²120/2Sin30.Cos60-tan135
=5*1/4 + 1/2 + 4*3/(2 * 1/2 * 1/2 )-(-1)
=5/4 + 1/2 +12*2 +1
=(5+2+100)/4
=107/4
Answered by
0
Answer:
Step-
by-step explanation:
Similar questions