Math, asked by niteshraj35, 10 months ago

Prove that (6)1/3 is an irrational number​

Answers

Answered by mass32
7

(6*3+1)/3=19/3=6.33333333.......

its repeating and reoccurring therefore its irrational no.

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Answered by pinquancaro
6

Proved below that 6^{\frac{1}{3}} is an irrational number.

Step-by-step explanation:

To prove : 6^{\frac{1}{3}} is an irrational number ?

Proof :

Assume that 6^{\frac{1}{3}} is rational.

Then it can be written as 6^{\frac{1}{3}}=\frac{n}{m} for some integers n and m which are co-prime.

Cubing root both side,

6=\frac{n^3}{m^3}

So n³ must be divisible by 6 and hence n must be divisible by 6.

Let n = 6p for some integer p.

6=\frac{(6p)^3}{m^3}

6=\frac{6^3p^3}{m^3}

So m³ and hence m must be divisible by 6.

But n and m where co-prime so they can not have any factors in common so we have a contradiction.

So 6^{\frac{1}{3}} must not be rational.

Hence it is irrational.

#Learn more

Proving irrational number s  Prove  3√2

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