Math, asked by shaily16, 7 months ago

Prove that √6.(√2+√3)[cosec 60°/2-cos 45°] = -1

Answers

Answered by muralireddy55

0

Answer:

4.967127833

Step-by-step explanation:

root 6.(root2+root3)[cosec 60°/2-cos 45°]=-1

5.967127833-1

=4.967127833

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