Question

Prove that 6-2√7 is irrational .
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Answer 1

Answer:

Step-by-step explanation:

LET US ASSUME THAT 6-2√7 IS RATIONAL ,THEN THERE EXISTS TWO INTEGERS p and q such that,

6-2√7=p/q and q is not equal to zero

-2√7=p-6q/q

√7=p-6q/-2q

we know that p-6q/-2q is rational ,but √7 is irrational .

this leads to contradiction. therefore our assumption that 6-2√7 is wrong hence it is an irrational number

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