Question

prove that 6√2 is an irrational number​

Answer 1

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Let us assume that 6+2√3 is rational,

so,

$6\sqrt{2} = \frac{a }{b}$

where a and b are co prime

$\sqrt{2} = \frac{a}{6b}$

we know that √2 is rational but it is shown in the form of

$\frac{p}{q}$

so, this contradiction is arissen because of our wrong assumption,

so,

6√2 is irrational

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hops this may help you

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