Question

prove that √6+√2 is irrational​

Answer 1

Answer:

hey mate

Let √6+√2 be rational number

√6+√2=p/q

√2=p/q-√6

√2=p-√q6/q

S.O.B.S

2=p^2+36q-12√6/q^2

2q^2-p^2-36q=-12√6

√6=2q^2-p^2-36q/-12

as 2q^2-p^2-36q/-12 is in p/q form it is rational number so √6 should be rational number

but in general √6 is irrational.

so our assumption is wrong

it is a contradiction

therefore √6+√2 is an irrational no.

.

.

.

.

hope it's help u

#isha

Answer 2

Answer:

please mark me as brainlist then I will follow u

Step-by-step explanation:

Let √6+√2 be rational number

√6+√2=p/q

√2=p/q-√6

√2=p-√q6/q

S.O.B.S

2=p^2+36q-12√6/q^2

2q^2-p^2-36q=-12√6

√6=2q^2-p^2-36q/-12

as 2q^2-p^2-36q/-12 is in p/q form it is rational number so √6 should be rational number

but in general √6 is irrational.

so our assumption is wrong

it is a contradiction

therefore √6+√2 is an irrational number