prove that 6 +√2is irrational number
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Step-by-step explanation:
Since a and b are two integers. Therefore (6-a/b)is a rational number and So root also is a rational number. But it is contradiction to fact root 2 =(6-a/b) is rational number. So we that 6+root 2 is an irrational number.
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0
Step-by-step explanation:
Since a and b are two integers. Therefore (6-a/b)is a rational number and So root also is a rational number. But it is contradiction to fact root 2 =(6-a/b) is rational number. So we that 6+root 2 is an irrational number.
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