prove that 6 + 3√5 is irrational
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0
Answer:
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Step-by-step explanation:
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Answered by
0
Step-by-step explanation:
Let us assume 6+
2
is rational. Then it can be expressed in the form
q
p
, where p and q are co-prime
Then, 6+
2
=
q
p
2
=
q
p
−6
2
=
q
p−6q
-----(p,q,−6 are integers)
q
p−6q
is rational
But,
2
is irrational.
This contradiction is due to our incorrect assumption that 6+
2
is rational
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